Explanation:
percentage yield = Actually yield÷ Theoretical yield × 100
The percent yield of magnesium oxide is 94.2%.
Percent yield exists as the percent ratio of actual yield to the theoretical yield. It is estimated to be the experimental yield divided by the theoretical yield multiplied by 100%. If the actual and theoretical yield exists exactly, the percent yield stands at 100%.
In chemistry, yield, also directed to as reaction yield, exists as a measure of the number of moles of a product created about the reactant consumed, acquired in a chemical reaction, usually represented as a percentage.
Write the balanced chemical equation.
2Mg + O₂ → 2MgO
Step 2: Compute the theoretical yield.
Based on the balanced chemical equation, 2 moles of Mg exists stoichiometrically equivalent to 2 moles of MgO.
The molar masses of Mg and MgO are 24.305 g/mol and 40.304 g/mol, respectively.
Theoretical yield= 1.2 g Mg *1mol Mg/24.305 g Mg*2 mol MgO/2 mol MgO/40.304 g MgO/1 mol MgO
=3.1839g
Calculate the percent yield,
Percent yield=actual yield/theoretical yield*100
=3.00 g/3.1839g*100
94.2%
Hence, the percent yield of magnesium oxide is 94.2%.
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