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2. A student wants to calculate the heat gained of 100 grams of water in order to
calculate the specific heat of a metal in the following problem. The water is
heated from 25C to 50C when the metal is added. The specific heat of water is
4.18 J/gºC. Use Q=m x CXAT*
5,225 J
10,450 J
20,900 J

Respuesta :

Taking into account the definition of calorimetry, the correct answer is the third option:  The heat exchanged is 10,450 J.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

The amount of heat (Q) necessary to vary the temperature of a mass (m) of a substance is proportional to the change in its temperature (∆T) and to that mass. So, the equation that allows calculating heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • c= 4.18 [tex]\frac{J}{gC}[/tex]
  • m=100 g
  • ΔT= Tfinal - Tinitial= 50 C -25 C= 25 C

Replacing in the expresion for calorimetry:

Q = 4.18[tex]\frac{J}{gC}[/tex]× 100 g× 25 C

Solving:

Q= 10,450 J

Finally, the correct answer is the third option:  The heat exchanged is 10,450 J.

Learn more:

  • brainly.com/question/11586486?referrer=searchResults
  • brainly.com/question/24724338?referrer=searchResults
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