Question

Question 10
Luella has a bag with three Hershey Kisses, two Reese's Cups, five York Peppermint
Patties, and a Jolly Rancher. What is the probability that Luella will pull out a Reese's
Cup, eat it, and then pull out another Reese's Cup? Write your answer as a simplified
fraction

Answer 1

Using the probability concept, it is found that there is a $\frac{1}{55}$ probability that Luella will pull out a Reese's  Cup, eat it, and then pull out another Reese's Cup.

A probability is the number of desired outcomes divided by the number of total outcomes.

• Initially, there are 11 sweets, 2 of which are Reese's Cups, thus, there is a $\frac{2}{11}$ probability of pulling a Reese's Cup.
• Then, there will be 10 sweets, of which 1 will be a Reese's Cup, thus, $\frac{1}{10}$ probability of pulling another Reese's Cup.

The probability of both events is the multiplication of the probabilities of each event, thus:

$p = \frac{2}{11} \times \frac{1}{10} = \frac{2}{110} = \frac{1}{55}$

$\frac{1}{55}$ probability that Luella will pull out a Reese's  Cup, eat it, and then pull out another Reese's Cup.

A similar problem is given at https://brainly.com/question/15536019