Question

What is the equation of the line with a gradient of −2 which passes through the point (3, −5)?

Answer 1

Answer:

y= mx + c

Step-by-step explanation:

y=mx+c

y= -2x+c

-5 = -2(3) +c

-5 = -6 +c

-5 + 6 = c

1 = c

therfore equation is y = -2x + 1