Question

Find the equation of a line perpendicular to y=2 that contains the point (−5,1).

Answer 1

Answer:

y = -1/2x - 5/2

Step-by-step explanation:

y = 2x – 1

Current slope is 2, perpendicular is opposite inverse which is -1/2.

y-intercept through point (-5, 0):

y = mx + b

0 = -1/2(-5) + b

0 = 5/2 + b

b = -5/2

Use the perpendicular slope and b above to form new equation of line:

y = mx + b

y = -1/2x - 5/2

Answer 2

Hello!Perpendicular lines have slopes that are opposite reciprocals. This means that if the slope of one line is 2, the slope of the line perpendicular to it would be the opposite reciprocal of 2 ($-\frac{1}{2}$)

First, write our equation in point-slope form:

$y-1=-\frac{1}{2}(x-(-5)$

$y-1=-\frac{1}{2}(x+5)$

$y-1=-\frac{1}{2} x-\frac{5}{2}$

$y=-\frac{1}{2}x-\frac{3}{2}$

And that's our equation in point-slope form.

Hope this helps you!

~Just a joyful teen

$SilentNature\\(GraceRosalia)$