The pressure change is an illustration of an arithmetic progression.
The atmospheric pressure at 50000 feet is 11.3 kPa
The given parameters are:
[tex]\mathbf{a = 101.3}[/tex] --- the first term
[tex]\mathbf{d = -1.8 per 1000}[/tex] -- common difference
At 50000 feet, the number of increment in altitude is
[tex]\mathbf{n = \frac{50000}{1000}}[/tex]
[tex]\mathbf{n = 50}[/tex]
So, the atmospheric pressure at 50000 feet is:
[tex]\mathbf{T_{50} = 101.3 - 1.8 \times 50}[/tex]
[tex]\mathbf{T_{50} = 101.3 - 90}[/tex]
[tex]\mathbf{T_{50} = 11.3}[/tex]
Hence, the atmospheric pressure at 50000 feet is 11.3 kPa
Read more about arithmetic progressions at:
https://brainly.com/question/13989292