Answer:
About 4.79 moles of oxygen.
Explanation:
We want to determine the amount of moles of oxygen are present in 0.798 moles of Mg(IO₃)₂.
From the chemical formula, we can see that there are six atoms of oxygen for every molecule of Mg(IO₃)₂. Therefore, we can say that there are six moles of oxygen for every mole of Mg(IO₃)₂. This yields the following ratio:
[tex]\displaystyle \frac{6\text{ mol O}}{1 \text{ mol Mg(IO$_3$)$_2$}}[/tex]
Multiplying this by the initial value yields:
[tex]\displaystyle 0.798 \text{ mol Mg(IO$_3$)$_2$} \cdot \displaystyle \frac{6\text{ mol O}}{1 \text{ mol Mg(IO$_3$)$_2$}} = 4.79 \text{ mol O}[/tex]
In conclusion, there are about 4.79 moles of oxygen present in 0.798 moles of Mg(IO₃)₂.
