Question

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Answer 1

Answer:

B

Step-by-step explanation:

To solve this problem we need to use order of operations or GEMDAS

First the Groupings which is the ()

Next is the Exponents,

3^6 = 729

y^-5 = y^-5 (Since it is a variable there is really nothing we can do about it)

Next is the other set of () outside our fraction (the ^2)

(Note: We really shouldn't have solved the exponents but just have placed them there but I just wanted to show you how that would look like.)

(3^6)^2 = 3^12

(y^-5)^2 = y^10

Meaning, the answer would be B

Hope this helps (Make sure to check it though)

Answer 2

Answer:

Answer B is correct

Step-by-step explanation:

Before, solving this let us get to know some points.

⇒ $(a^{x}) ^{y} = a^{xy}$

⇒ $a^{x} *a^{y} =a^{x+y}$

⇒ $\frac{a^{x} }{a^{y} } =a^{x-y}$

⇒ $a^{-x} =\frac{1}{a^{x} }$

⇒ $\frac{1}{a^{-x} } =a^{x}$

Let us solve the question now.

( 3⁶ ÷ y⁻⁵)²

3⁽ ⁶ ˣ ² ⁾ ÷ y ⁽ ⁻⁵ ˣ ²⁾

3¹² ÷ y⁻¹⁰

3¹² ÷ $\frac{1}{y^{-10} }$

3¹² × y¹⁰

Therefore, Answer B is correct.