Question

An airplane travels 250 km due east, then turns and travels 180 km [E 60°S]. Determine the resulting travel displacement for this plane.​

Answer 1

Answer:

388.56km[E13degS]

Explanation:

Δdx = Δd1x + Δd2x

Δdx = 250km [E]+ 180sin(60) [E]

Δdx = 405.88 km [E]

Δdy = Δd1y + Δd2y

Δdy = 0 + 160cos(60) [S]

Δdy = 90km [S]

Δdt = √(Δdx)^2+(Δdy)^2

Δdt = √164738.57+8100

Δdt = 398.85km

tanθ = Δdy/Δdx

tanθ = 90/388.56

θ = tan-1(90/388.56)

θ = 13.04 deg