Respuesta :
congruent sides have equal legnth
the shorter side is the last side
if the congruent sides are x and the shorter one is y, and x is 1 longer than y then
x=1+y
perimiter=x+x+y
x=1+y
perimiter=1+y+1+y+y=3y+2
square is 4s
each side (s) is 2 less than y
s=y-2
square is 4(y-2)=4y-8
4y-8=3y+2
minus 3y both sides
y-8=2
add 8 both sides
y=10
the legnth is 10 units
the shorter side is the last side
if the congruent sides are x and the shorter one is y, and x is 1 longer than y then
x=1+y
perimiter=x+x+y
x=1+y
perimiter=1+y+1+y+y=3y+2
square is 4s
each side (s) is 2 less than y
s=y-2
square is 4(y-2)=4y-8
4y-8=3y+2
minus 3y both sides
y-8=2
add 8 both sides
y=10
the legnth is 10 units
Answer:
10 units
Step-by-step explanation:
Let the shortest side be x
Now since we are given that The congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle.
So, the length of the congruent sides (each) = x+1
Thus the perimeter of triangle = sum of all sides
= x+x+1+x+1
=3x+2
Now we are given that The perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle.
Side of square = x-2
So, perimeter of square = 4*side
=4(x-2)
=4x-8
Now since the perimeter of the triangle and square are equal
So,[tex]3x+2=4x-8[/tex]
[tex]10=x[/tex]
Hence the shortest side of the triangle is 10 units.