Question

Under what pressure will a scientist need to store 0.400 moles of gas if the container has a volume of 200.0 mL and the temperature is kept at 23.0 C?

Answer 1

Answer: 48.60 atm

Explanation: Using ideal gas equation:

$PV=nRT$

$P=\frac{nRT}{V}$

P= pressure = ? atm

V= volume =$200ml=0.2L$  

n = no of moles = 0.400

R= gas constant =0.0821 Latm/molK

T = Temperature $=23^0C=(23+273)K=296K$

$P=\frac{0.400\times 0.0821\times 296K}{0.2L}=48.60atm$