Question

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the student use to make the sample? Use mc020-1.jpg. 3.70 mL 16.7 mL 30.0 mL 83.3 mL

Answer 1

A) 3.70 mL   B)   16.7 mL   C) 30.0 mL   D) 83.3 mL

It is C 30.0 mL

Answer 2

Answer is 30.0mL

according to the question dilution is performed by the student which can be calculated with the help of :

                          $M_{1}V_{1}=M_{2}V_{2}$     EQUATION (1)

Here, we have:

 $M_{1}$ = 3M

  $V_{1}$  = y mL

$M_{2}$= 1.80 M

$V_{2}$ = 50.0mL

putting the known values in equation (1) which will give us value of $V_{1}$

                                         3.00× y =1.80 ×50.0

                                                         y= 30.0mL