Respuesta :
There are 6 choose 3 possibilities (combinations).
6C3 = 6!/(6-3)!3!
= 6•5•4/(3•2•1)
= 120/6
= 20
With 20 possibilities, there is a 1 in 20 chance that she will choose her favorite three.
The answer is Option C. 1/20.
6C3 = 6!/(6-3)!3!
= 6•5•4/(3•2•1)
= 120/6
= 20
With 20 possibilities, there is a 1 in 20 chance that she will choose her favorite three.
The answer is Option C. 1/20.
The number of ways of choosing 3 objects from 6 objects is 6C3.
6C3 = 6!/[3!(6-3)!] = 6!/(3!3!) = 6*5*4/(3*2*1) = 20
This is the number of outcomes in the sample space. One of those outcomes will yield her 3 favorite sweaters.
So, the probability is 1/6C3 = 1/20
Therefore, the answer is Option 3.
6C3 = 6!/[3!(6-3)!] = 6!/(3!3!) = 6*5*4/(3*2*1) = 20
This is the number of outcomes in the sample space. One of those outcomes will yield her 3 favorite sweaters.
So, the probability is 1/6C3 = 1/20
Therefore, the answer is Option 3.