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The structure should the code have should be letter C which is Select a number from {1, 2, 3, 4, 5, 6} and a vowel.
The structure should the code have should be letter C which is Select a number from {1, 2, 3, 4, 5, 6} and a vowel.
Answer:
The code should have the structure C.
Step-by-step explanation:
Given : Two spies have to communicate using secret code. They need to create exactly 30 possible precoded messages, using a single number and letter.
To Find: Which structure should the code have?
Solution:
The structure that have 30 possible outcomes , the code should have that structure .
Option A: Select a number from {1, 2, 3, 4} and a vowel
Since we are given that the code contains one number and one letter
No.of vowels = {a,e,i,o,u}=5
Out of these five we will choose only one
We are supposed to choose a number from {1, 2, 3, 4}
Out of these four numbers we will choose only one
Now to find no. of possible outcomes we will use combination
Formula : [tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]
So, no. of possible outcomes from option A :
[tex]^5C_1\times ^4C_1[/tex]
[tex]\frac{5!}{1!(5-1)!} \times \frac{4!}{1!(4-1)!}[/tex]
[tex]\frac{5!}{1!(4)!} \times \frac{4!}{1!(3)!}[/tex]
[tex]5 \times 4[/tex]
[tex]20[/tex]
Thus no. of possible outcomes from Option A is 20.
Option B: Select a number from {1, 2, 3, 4, 5} and a vowel.
Since we are given that the code contains one number and one letter
No.of vowels = {a,e,i,o,u}=5
Out of these five we will choose only one
We are supposed to choose a number from {1, 2, 3, 4,5}
Out of these five numbers we will choose only one
So, no. of possible outcomes from option B :
[tex]^5C_1\times ^5C_1[/tex]
[tex]\frac{5!}{1!(5-1)!} \times \frac{5!}{1!(5-1)!}[/tex]
[tex]\frac{5!}{1!(4)!} \times \frac{5!}{1!(4)!}[/tex]
[tex]5 \times 5[/tex]
[tex]25[/tex]
Thus no. of possible outcomes from Option B is 25.
Option C: Select a number from {1, 2, 3, 4, 5, 6} and a vowel.
Since we are given that the code contains one number and one letter
No.of vowels = {a,e,i,o,u}=5
Out of these five we will choose only one
We are supposed to choose a number from {1, 2, 3, 4,5,6}
Out of these six numbers we will choose only one
So, no. of possible outcomes from option C :
[tex]^5C_1\times ^6C_1[/tex]
[tex]\frac{5!}{1!(5-1)!} \times \frac{6!}{1!(6-1)!}[/tex]
[tex]\frac{5!}{1!(4)!} \times \frac{6!}{1!(5)!}[/tex]
[tex]5 \times 6[/tex]
[tex]30[/tex]
Thus no. of possible outcomes from Option C is 30.
So, Option C is correct
Option D: Select a number from {1, 2, 3, 4, 5} and a consonant
Since we are given that the code contains one number and one letter
No.of consonants = 21
Out of these twenty one we will choose only one
We are supposed to choose a number from {1, 2, 3, 4,5}
Out of these five numbers we will choose only one
So, no. of possible outcomes from option C :
[tex]^5C_1\times ^21C_1[/tex]
[tex]\frac{5!}{1!(5-1)!} \times \frac{21!}{1!(21-1)!}[/tex]
[tex]\frac{5!}{1!(4)!} \times \frac{21!}{1!(20)!}[/tex]
[tex]5 \times 21[/tex]
[tex]105[/tex]
Thus no. of possible outcomes from Option D is 105.
Hence Option C is correct because no. of possible outcomes in that case is 30 .
So, the code should have the structure C.
