Question

In a pulley system, a 5-newton weight is to be lifted 2 meters. The rope is pulled 10 meters. The input force is two newtons.

The IMA = .

The AMA = .

The efficiency = %.

Answer 1

The answers to the problem are as follows:

MA= 5 

IMA= input distance/ output distance, 5 

AMA= output force/ input force, 5/2


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Answer 2

Explanation:

It is given that,

Input force, $F_i=2\ N$

Output force, $F_o=5\ N$

Input distance, $d_i=10\ N$

Output distance, $d_o=2\ N$

1. IMA of a machine is the ratio of input distance to the output distance. It is given by :

$IMA=\dfrac{d_i}{d_o}=\dfrac{10}{2}=5$

2. AMA is the actual mechanical advantage of the machine. It is the ratio of output force to the input force. It is given by :

$AMA=\dfrac{F_o}{F_i}=\dfrac{5}{2}$

3. The efficiency of the machine is the percentage of output work to the input work.

$\eta=\dfrac{W_o}{W_i}\times 100$

$\eta=\dfrac{F_o\times d_o}{F_i\times d_i}\times 100$

$\eta=\dfrac{5\times 2}{2\times 10}\times 100$

$\eta=50\%$

Hence, this is the required solution.