Question

A student bikes to school by traveling first dN = 1.10miles north, then dW = 0.400miles west, and finally dS = 0.100miles south.

If a bird were to start out from the origin (where the student starts) and fly directly (in a straight line) to the school, what distance db would the bird cover?

You will now find the same quantity algebraically, without the need to use much geometry. Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking.
Let d⃗ N be the displacement vector corresponding to the first leg of the student's trip. Express d⃗ N in component form.

Answer 1

The answer to the problem is as follows:

The bird will travel the hypotenuse of a right angled triangle with one side 1.1mile - 0.100 miles = 1.00 miles and other side = 0.400 miles bird's travel path = √(1.00² + 0.400²) = 1.077 miles.

You can continue my solution until you find the answer that is required.

I hope my answer has come to your help. God bless and have a nice day ahead!