Question

A uniform horizontal rod of mass M and length l rotates with angular velocity ω about a vertical axis through its center. Attached to the end of the rod is a small mass m. Determine the angular momentum of the system about the axis.

Answer 1

The solution to the problem is as follows:

Then, it's just... 

L = Iω where... 

ω = angular velocity 

I = moment of inertia 

So... 

L = ML²/12 * ω 

I hope my answer has come to your help. God bless and have a nice day ahead!