Question 3.3. Marco is selling floral arrangements. Each arrangement uses 1 vase and 11 orchids. Each vase costs Marco $4.00. Let C be the total cost of the arrangement and r be the cost of 1 orchid. Which equation should Marco use to find the total cost of each arrangement?

(Points : 1)
A. 11 = C +4r
B. 11C = r + 4
C. C = 4r + 1
D. C = 11r + 4

In question 3, You don't know the cost of an orchid, so that is r. You have 11 orchids per vase, so that is a cost of 11r per vase. A vase costs $4. 11r + 4 would be the total cost. So, the last choice would be your answer which is:

C = 11r + 4

I hope my answer has come to your help. God bless and have a nice day ahead!

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astha8579 astha8579 · Answer 2 · 2022-04-01T12:26:51+02:00

The equation that Marco should use to find the total cost of each arrangement is given by: Option D: C = 11r + 4

How to form mathematical expression from the given description?

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

For this case, we're provided that:

C = total cost of the arrangement
r = cost of 1 orchid
cost of vase = $4.00

Each arrangement uses 1 vase, and 11 orchid

Total cost C = Cost of 11 orchids + Cost of vase
Cost of 11 orchids = r + r + ... + r (11 times) = [tex]11 \times r = 11r[/tex] (in dollars)

(we don't write symbols like of currency generally, and understand it from context. Also, sign of multiplication is often hidden if there are non numeric symbols and numbers being multiplied are written together)

Thus, total cost is evaluated as:

C = 11r + 4 (in dollars).

Thus, the equation that Marco should use to find the total cost of each arrangement is given by: Option D: C = 11r + 4

Learn more about linear equations here:

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