The work function of cesium is 1.96 eV. If radiation of wavelength 4.00 × 10^2 nm is incident on the surface, find the kinetic energy of the ejected photoelectrons in eV and the speed of the ejected electrons.

Respuesta :

I have a note here that might help you solve the problem on your own:

According to the law of conservation of energy 

The energy of the photon is used in overcoming the workfunction of the metal, and the excess energy goes as the kinetic energy of the electron. 

Photon Energy = Work function of Cs + KE of electron 


I hope my guide has come to your help. God bless and have a nice day ahead!
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