Question

Brianna is graphing the function f(x) = x2 + 6x + 5. What x-intercepts should Brianna use to graph f(x)?

–5 and –1
–5 and 1
–1 and 5
1 and 5

Answer 1

the answer is
–5 and –1
proof
for  f(x) = x2 + 6x + 5, f(-5)=25-30+5 = 0, x=-5, y=0
     f(-1)= 1-6+5=6-6=0, x=-1, and y=0
the x-intercepts are –5 and –1

Answer 2

The function f(x) = x^2 + 6x + 5 is a quadratic function, and Brianna should use -1 and -5 as the x-intercepts of the function

What are x-intercepts?

The x-intercepts of a function are the points where the function crosses the x-axis

The function is given as:

f(x) = x^2 + 6x + 5

Expand the function

f(x) = x^2 + x + 5x + 5

Factorize the function

f(x) = (x +1)(x + 5)

Set to 0

(x + 1)(x + 5) = 0

Solve for x

x = -1 and x = -5

Hence, Brianna should use -1 and -5 as the x-intercepts of the function

Read more about x-intercepts at:

https://brainly.com/question/3951754