Respuesta :
y=2/x² +3
let's find f and g
y=f(g(x))=2/x² +3, y-3= 2/x² , so f^-1(y)= y-3= 2/x² = g(x)
so g(x) =2/x²
but y = 2/x² +3, so y= g(x)+3= f(g(x)), consequently, f(x) = x+3
finally f(x) = x+3, and g(x)=2/x²
let's find f and g
y=f(g(x))=2/x² +3, y-3= 2/x² , so f^-1(y)= y-3= 2/x² = g(x)
so g(x) =2/x²
but y = 2/x² +3, so y= g(x)+3= f(g(x)), consequently, f(x) = x+3
finally f(x) = x+3, and g(x)=2/x²
Answer: g(x) =[tex]x^2[/tex]
and f(x) =[tex]\frac{2}{x+3}[/tex]
Step-by-step explanation:
[tex]y=\frac{2}{x^2+3}[/tex]
To find f(x) and g(x) such that
[tex]y=f(g(x))=\frac{2}{x^2+3}[/tex],
Then only one possible answer is g(x) =[tex]x^2[/tex]
and f(x) =[tex]\frac{2}{x+3}[/tex] such that
[tex]\text{the composite function will be }\ f(g(x))=f(x^2)=\frac{2}{(x^2)+3}=\frac{2}{x^2+3}[/tex]
Thus, g(x) =[tex]x^2[/tex]
and f(x) =[tex]\frac{2}{x+3}[/tex]