Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?



12.0 M * 0.500 l = 6.0 M * V2



12.0 M * 6.0 M = 0.500 l * V2



12.0 M * V1 = 6.0 M * 0.500 l



6.0 M * V1 = 12.0 M * 0.500 l



(12.0 M + 6.0 M) = 0.500 l * V2