Respuesta :

x^1/2 y^5/2 = (xy)^1/2 * y^2 = y^2 radical xy.

Answer:

The given expression when reduced in simplified form, reduces to

[tex]=x^{\frac{1}{2}}\times y^{\frac{5}{2}}\\\\=x^{\frac{1}{2}}\times y^{\frac{1}{2}}\times y^{2}\\\\=y^2\sqrt{xy}\\\\=y^2{\text{radical}}(x y)[/tex]

or

[tex]=x^{\frac{1}{2}}\times y^{\frac{5}{2}}\\\\={\text{Radical}}(x\times y^5)[/tex]

Here, Radical = Square root

Used the following law of indices

[tex]a^{\frac{1}{2}}=\sqrt{a}[/tex]

Option C: y²*Radical (x y)

Radical =Either Square root, or cube root ,.....fifth root,....

Option A : [tex]{\text{Radical}}(x\times y^5)[/tex]

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