Question

A class consists of 60% men and 40% women. Blonde men compose 25% of the class, and blond women make up 20% of the class. If a student is chosen at random and is found to be a male, what is the probability that the student is blond?

Answer 1

The probability that a selected male student is blond = 25/60 = 5/12 = 0.42

Answer 2

Answer:

The probability that the student is blond and chosen be men is 65%.

Step-by-step explanation:

Given : A class consists of 60% men and 40% women. Blonde men compose 25% of the class, and blond women make up 20% of the class. If a student is chosen at random and is found to be a male.

To find : What is the probability that the student is blond?

Solution :  

Let the probability of men is 60% P(M)=0.6

The probability of women is 40% P(W)=0.4

Let B is the person blonde makeup.

The probability of blonde men is 25% P(B/M)=0.25

The probability of blonde women is 20% P(B/W)=0.20

We have to find the probability that the student is blonde and choosen is men i.e. P(M/B)

Applying Baye's Theorem,

$P(M/B)=\frac{P(B/M)\times P(M)}{P(B/M)\times P(M)+P(B/W)\times P(W)}$

$P(M/B)=\frac{0.25\times 0.6}{0.25\times 0.6+0.20\times 0.4}$

$P(M/B)=\frac{0.15}{0.15+0.08}$

$P(M/B)=\frac{0.15}{0.23}$

$P(M/B)=0.65$

Therefore, The probability that the student is blond and chosen be men is 65%.