Question

How many sulfide ions are in 15 dg of sodium sulfide?
O 1.16 x 1022
O 3.04 x 1028
O 5.76 x 1029
O 6.02 x 1023
O 3.13

Answer 1

There are 5.78 × 10^20 sulfide ions in sodium sulfide

The formula of the compound is Na2S. The molar mass of the compound is calculated as follows; 2(23) +32 = 46 + 32 = 78 g/mol

Number of moles of Na2S = 0.15 g/ 78 g/mol = 0.0019 moles

Since there is 1 mole of Na^+ and 2 moles of S^2- in Na2S, the number of S^2- ions in  0.19 moles of Na2S is 0.00096 moles of S^2-.

If 1 mole of S^2- contains 6.02  × 10^23

0.095 moles of S^2- contains 0.00096 moles × 6.02  × 10^23/ 1 mole

= 5.78 × 10^20 sulfide ions

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