Question

1. Line FG contains points F (3, 7) and G (−4, −5). Line HI contains points H (−1, 0) and I (4, 6). Lines FG and HI are

parallel

perpendicular

neither

2. Line AB contains points A (8, −4) and B (1, −5). The slope of line AB is

−7

negative 1 over 7

1 over 7

7

Answer 1

1. >> neither
2. >> m= $- \frac{1}{7}$ >> negative 1 over 7

Answer 2

Answer:

1. Neither

2. 1 over 7

Step-by-step explanation:

We know that the formula for slope joining the points $( x_{1} ,y_{1} )$ and $( x_{2} ,y_{2} )$ is given by $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$.

1. We have the line FG having end points ( 3,7 ) and ( -4,-5 ). The slope of this line is given by,

$m_{FG}=\frac{-5-7}{-4-3}$

i.e. $m_{FG}=\frac{-12}{-7}$

i.e. $m_{FG}=1.714$

Also, the line HI is given with end points ( -1,0 ) and ( 4,6 ). Its slope is given by,

$m_{HI}=\frac{6-0}{4+1}$

i.e. $m_{HI}=\frac{6}{5}$

i.e. $m_{HI}=1.2$

Since, neither the slope of FG and HI are equal nor their product is -1.

Hence, FG and HI are neither parallel nor perpendicular respectively.

2. We have the line AB with end points ( 8,-4 ) and ( 1,-5 ). So, the slope of AB is,

$m_{AB}=\frac{-5+4}{1-8}$

i.e. $m_{AB}=\frac{-1}{-7}$

i.e. $m_{AB}=\frac{1}{7}$

Hence, slope of AB is 1 over 7.