Question

A bus moves away from a bus stop in a straight line. It moves 10 meters by the end of the 1st second, 20 meters by the end of the 2nd second, and 30 meters by the end of the 3rd second. How many meters away is the bus from the bus stop after 10 seconds?
a.

100

c.

120
b.

110

d.

190

Answer 1

The answer would be A 100 becuase you take the number of seconds multiplied by ten so then it would end up being 10 multiplied by 10 which equals 100
 hope this helps

Answer 2

Answer:

Option a. 100 meters.

Step-by-step explanation:

A bus moves away from bus stop in a straight line. After 1 second it was 10 meters away, after 2 seconds it was 20 meters and after 3 seconds it was 30 meters away.

In this way bus forms an arithmetic sequence

10, 20, 30, 40........up to 10 terms.

nth term of an arithmetic sequence is represented by

$T_{n}=a+(n-1)d$

Here a = 10 and d = common difference = 10

Therefore 10th term = 10 + (10-1)10 = 10 + 90 = 100

Therefore after 10 seconds bus will be 10 meters away from the bus stop.