Respuesta :
f(x) = 2*x^3 + 9x^2 -8x - 36
= 2x ( x^2 - 4) + 9( x^2 -4)
= (2x + 9)(x^2 - 4)
= (2x + 9)(x-2)(x+2)
x = 2, -2 , -9/2
ans. = d. x=2
= 2x ( x^2 - 4) + 9( x^2 -4)
= (2x + 9)(x^2 - 4)
= (2x + 9)(x-2)(x+2)
x = 2, -2 , -9/2
ans. = d. x=2
Answer: Option d is correct that is x=2 is the another zero of the given polynomial
Explanation:
We have been given the polynomial [tex]2x^3+9x^2-8x-36[/tex]
Zero of any polynomial is the point where the value of function is zero
Here we are given one zero at x=-2 if we substitute the value x=-2 in the given polynomial we will get zero
Now to find other point where we will get the solution or we will get zero
First we substitute x=8 in the given polynomial we will get
[tex]2(8)^3+9(8)^2-8(8)-36\\\\=1500\neq0[/tex] Hence, not the zero of given polynomial
Similarly, when we substitute x=4 in the given polynomial we will get
[tex]2(4)^3+9(4)^2-8(4)-36\\\\=204\neq0[/tex] Hence, not the zero of given polynomial
Similarly, substitute x=3 in the given polynomial we will get
[tex]2(3)^3+9(3)^2-8(3)-36\\\\=75\neq0[/tex] Hence, not the zero of given polynomial
Substitute x=2 in the given polynomial we will get
[tex]2(2)^3+9(2)^2-8(2)-36\\\\=0[/tex] Hence, the zero of the polynomial
Therefore Option d is correct.