Respuesta :
ANSWER
[tex]x = - 2 \pm i[/tex]
EXPLANATION
We use the method of completing the squares.
The equation is
[tex]3 {x}^{2} = - 12x - 15[/tex]
We rewrite the above equation to obtain;
[tex]3 {x}^{2} + 12x = - 15[/tex]
We divide through by 3 to obtain;
[tex] {x}^{2} + 4x = - 5[/tex]
We add half the coefficient of
[tex]x[/tex]
to both sides of the equation to get,
[tex] {x}^{2} + 4x + {2}^{2} = - 5 + {2}^{2} [/tex]
The right hand side is now a perfect square.
[tex]{(x + 2)}^{2} = - 1[/tex]
We now take square root of both sides to get;
[tex]x + 2 = \pm \sqrt{ - 1} [/tex]
We add -2 to both sides,
[tex]x = - 2 \pm \sqrt{ - 1} [/tex]
We simplify to obtain,
[tex]x = - 2 \pm i[/tex]
[tex]x = - 2 \pm i[/tex]
EXPLANATION
We use the method of completing the squares.
The equation is
[tex]3 {x}^{2} = - 12x - 15[/tex]
We rewrite the above equation to obtain;
[tex]3 {x}^{2} + 12x = - 15[/tex]
We divide through by 3 to obtain;
[tex] {x}^{2} + 4x = - 5[/tex]
We add half the coefficient of
[tex]x[/tex]
to both sides of the equation to get,
[tex] {x}^{2} + 4x + {2}^{2} = - 5 + {2}^{2} [/tex]
The right hand side is now a perfect square.
[tex]{(x + 2)}^{2} = - 1[/tex]
We now take square root of both sides to get;
[tex]x + 2 = \pm \sqrt{ - 1} [/tex]
We add -2 to both sides,
[tex]x = - 2 \pm \sqrt{ - 1} [/tex]
We simplify to obtain,
[tex]x = - 2 \pm i[/tex]