Question

if a + b = 10 what is the value of 2(a + b) + a + b/6 + (a + b) ^ 2 - 2

Answer 1

Answer:

$\frac{359}{3}$ or $119~\frac{2}{3}$

Step-by-step explanation:

Let $x=a+b$. Then, the expression just reduces to $2x+\frac{x}{6}+x^2-2$.

But we know that $a+b=x=10$!

Plugging in for $x$ gives $2(10)+\frac{10}{6}+10^2-2=20+\frac{5}{3}+100-2=118+\frac{5}{3}=\frac{359}{3}$.

So, the answer is $\boxed{\frac{359}{3}}$ and we're done!

Answer 2

Answer:

${ \rm{2(a + b) + \frac{a + b}{6} + {(a + b)}^{2} - 2}}$

• substitute (a + b) with 10:

$= { \tt{2(10) + \frac{10}{6} + {(10)}^{2} - 2 }} \\ \\ = { \tt{20 + \frac{10}{6} + 100 - 2}} \\ \\ { \boxed{ \tt{ = 119 \frac{2}{3} }}}$