Respuesta :

f(x+2)= -x^2 -4. Use basic transformations

Answer:

The standard equation of parabola:

[tex]y =a(x-h)^2+k[/tex]             ....[1]

where, vertex = (h, k) and a is any constant value.

As per the statement:

In the given graph of parabola:

Vertex of parabola = (-2, -4)

⇒h = -2 and k= -4

Substitute in [1] we have;

[tex]y =a(x+2)^2-4[/tex]               ....[2]

Since, the graph of parabola cuts at y-axis at (0, -8)

Substitute this point in [2] to solve for a, we have;'

[tex]-8=a(0+2)^2-4[/tex]

⇒[tex]-8=a(2)^2-4[/tex]

Add 4 to both sides we have;

[tex]-4=a(2)^2[/tex]

⇒[tex]-4=4a[/tex]

Divide both sides by 4 we have;

a = -1

then, the equation become:

[tex]y =-1(x+2)^2-4[/tex]

Therefore, the equation of the graph is, [tex]y =-(x+2)^2-4[/tex]

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