Respuesta :
Answer:
1.225m
Explanation:
acceleration due to gravity=9.8m/s^2
initial velocity of golf(u)=0m/s [As it falls from rest]
time(t)=1/2s
Now,
s=ut+1/2at^2
0*1/2+1/2*9.8*(1/2)^2
1.225m
Therefore, the golf falls 1.225m.
Answer:
• This is called motion under gravity, so we consinder only vertical motion and neglect horizontal motion.
• From the second equation of motion;
[tex] \hookrightarrow \: { \boxed{ \rm{S = ut + \frac{1}{2} gt {}^{2} }}} \\ [/tex]
- S is the displacement
- u is the initial velocity
- g is acceleration due to gravity, g = 10
- t is the time taken
• Assuming the ball is dropped from rest:
[tex]{ \tt{S = (0 \times \frac{1}{2} ) + ( \frac{1}{2} \times 10)( { \frac{1}{2} )}^{2} }} \\ \\ { \tt{S = \frac{1}{8} \times 10}} \\ \\ { \tt{S \approx1 \: meter}}[/tex]