Respuesta :

Answer:

1.225m

Explanation:

acceleration due to gravity=9.8m/s^2

initial velocity of golf(u)=0m/s [As it falls from rest]

time(t)=1/2s

Now,

s=ut+1/2at^2

0*1/2+1/2*9.8*(1/2)^2

1.225m

Therefore, the golf falls 1.225m.

Answer:

• This is called motion under gravity, so we consinder only vertical motion and neglect horizontal motion.

• From the second equation of motion;

[tex] \hookrightarrow \: { \boxed{ \rm{S = ut + \frac{1}{2} gt {}^{2} }}} \\ [/tex]

  • S is the displacement
  • u is the initial velocity
  • g is acceleration due to gravity, g = 10
  • t is the time taken

• Assuming the ball is dropped from rest:

[tex]{ \tt{S = (0 \times \frac{1}{2} ) + ( \frac{1}{2} \times 10)( { \frac{1}{2} )}^{2} }} \\ \\ { \tt{S = \frac{1}{8} \times 10}} \\ \\ { \tt{S \approx1 \: meter}}[/tex]

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