At how many points does the graph of the function below intersect the x-axis?
y = 25x^2-10x+1

There is just one point does the graph of the function intersect x-axis.
Option B is correct.
The graph of a function is the collection of all ordered pairs of the function.
Graphing functions is drawing the curve that represents the function on the coordinate plane. If a curve (graph) represents a function, then every point on the curve satisfies the function equation.
For graphing quadratic function also, we can find some random points on it. But this may not give a perfect U-shaped curve. This is because, to get a perfect U-shaped curve, we need where the curve is turning. i.e., we have to find its vertex. After finding the vertex, we can find two or three random points on each side of the vertex and they would help in graphing the function.
Given equation
[tex]y = 25x^2-10x+1[/tex]
One of the standardized forms is [tex]y = a^2+bx+c[/tex]
Where [tex]x= \frac{-b \pm \sqrt{b^{2} -4ac} }{2a}[/tex]
Consider the part [tex]b^{2}-4ac[/tex]
If this is negative then there is no intersection
It it is 0 then there is just one.
If it is greater than 1 there there are 2.
[tex]y = 25x^2-10x+1[/tex]
[tex]b^{2}-4ac=(-10)^{2} -4(25)(1)= 100-100 =0[/tex]
Thus, there is just one point does the graph of the function intersect x-axis.
Find out more information about graph of a function here
brainly.com/question/9834848
#SPJ2