The solution of the given quadratic equation is x = (-5 ± √29)/2
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, the given equation
x² + 5x -1 = 0
we know, x = {-b±√(b²-4ac)}/2a
where, a = 1, b = 5 and c = -1
x = {-5 ± √(5²-4X1X(-1))}/2X1
x = (-5 ± √29)/2
Thus, the solution of the given quadratic equation is x = (-5 ± √29)/2.
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