Answer:
b. 1/5
Step-by-step explanation:
[tex] {10}^{2y} = 25[/tex]
[tex] { ({10}^{y}) }^{2} = {5}^{2} [/tex]
SQUARE ROOT ON BOTH SIDES
[tex] {10}^{y} = 5[/tex]
RECIPROCAL ON BOTH SIDES
[tex] \frac{1}{ {10}^{y} } = \frac{1}{5} [/tex]
[tex] {10}^{ - y} = \frac{1}{5} [/tex]
Answer:
y=.04 Does not change just because power of does, and sum does. Answer C
Step-by-step explanation:
10^2y=25
100y=25
100 x .04=25
10^-2y=-25