Answer:
maximum height: p(t) = Vo * t - 1/2 * g * t^2
p’(t) = v(t) = 0 = Vo - g*t. So, maximum height occurs when t = Vo / g
p(Vo / g) = Vo^2/g - 1/2 * g * (Vo/g)^2
Vo = 10 m / s. Let’s approximate g = 10 m / s^2
p(Vo / g) = 10^2 / 10 - 1/2 * 10 * (10/10)^2 = 10 - 5 = 5 meters (approximately)
Calculation of time:
v = u + gt
0 = 10√2 + (-10)t
-10√2 = -10t
2 = √2s
