Question

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● Correct explanation needed
● Need Statements also ​

Answer 1

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The smallest number which is divisible by 12 , 15 and 30 is their L.C.M , that is :

• 12 = 2 × 2 × 3

• 15 = 3 × 5

• 30 = 2 × 3 × 5

LCM = 2 × 2 × 3 × 5 = 60

hence, the required number is 60

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