Question

Which best describes the end behavior of y=7x^2?

As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) decreases.

As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) decreases.

As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) increases.

As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) increases.

Answer 1

As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) increases. 
because f(x) is a quadratic with lowest point at x=0

Answer 2

Answer:

Option C is correct.

as x > 0 increases, f(x) increases,

as x < 0 decreases, f(x) increase.

Step-by-step explanation:

Given the function: $y = 7x^2$

Degree of the polynomial states that the sum of the exponents of each variable in the expression.

The degree of $7x^2$ is 2 i.e Even

The  leading coefficient of the polynomial $7x^2$ is, 7 i.e, Positive.

End behavior of the polynomial is the behavior of the graph of  f(x) as x approaches positive infinity or negative infinity.

Also, the degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

Since, the degree of the given function is even and the leading coefficient is positive.

End behavior of the function$y = 7x^2$ is:

as $x \rightarrow +\infty$, then  $f(x) \rightarrow +\infty$

and

as  $x \rightarrow -\infty$ , then  $f(x) \rightarrow +\infty$

Therefore, as x > 0 increases, f(x) increases.

As x < 0 decreases, f(x) increases.