You are given a soda can with a volume of 15 and a diameter of 2. You are asked what is the volume of a cone that fits perfectly inside the soda can.
Soda can is shaped like a cylinder so V = [tex] \pi [/tex](d²/4)h and the cone is V = [tex] \pi [/tex](d²/12)h.
15 = [tex] \pi [/tex](2²/4)h
h = 4.77
V = [tex] \pi [/tex](2²/12)(4.77) since the cone and the cylinder have the same base and height
V = 5
