1. let f(x)=-5x-4 and g(x)=6x-7. find f(x)+g(x)
A. -11x+3
B. x+3
C. -11x-11
D. x-11
2. let f(x)=3x+2 and g(x)=6x-7. find f(x)-g(x)
A. 3x-9
B. -3x+9
C. -3x-5
D. 2x-1
3. let f(x)=-5+3 and g(x)=6x-2. find f*g and its domain
A. -30x^2+28x-6; all real numbers except x=1/3
B. -15x^2-8x-12; all real numbers except x=3/5
C. -30x^2+28x-6; all real numbers
D. -15x^2-8x-12; all real numbers
Question 1: We have the following functions: [tex]f(x) = - 5x - 4
g(x) = 6x - 7[/tex] We have then: For f (x) + g (x): We add both functions. We have then: [tex]f (x) + g (x) = (- 5x - 4) + (6x - 7)
f (x) + g (x) = (- 5x + 6x) + (-4 - 7)
f (x) + g (x) = x - 11[/tex] Answer: D. x - 11
Question 2: We have the following functions: [tex]f(x) = 3x + 2
g(x) = 6x - 7[/tex] We have then: For f (x) - g (x): We subtract both functions. We have then: [tex]f (x) - g (x) = (3x + 2) - (6x - 7)
f (x) - g (x) = (3x - 6x) + (2 + 7)
f (x) - g (x) = -3x + 9[/tex] Answer: B. -3x + 9 Question 3: We have the following functions: [tex]f(x) = -5x + 3
g(x) = 6x - 2[/tex] We have then: [tex]f (x)*g (x) = (-5x + 3)*(6x - 2)
[/tex] Rewriting we have: [tex]f (x)*g (x) = -30x^2 + 10x + 18x - 6
f (x)*g (x) = -30x^2 + 28x - 6[/tex] The domain of the function is all real because it has no restriction. Answer: C. -30x^2 + 28x - 6; all real numbers
