Respuesta :
Let x sq. ft be the area Melinda shovels per minute and y sq. ft be the area Paul shovels per minute.
1. Together they shoveled 450 square feet of sidewalk in 30 minutes, then
30x+30y=450.
2. Melinda shoveled for 20 minutes while Paul shoveled for 25 minutes to complete 345 square feet of driveway. Then
20x+25y=345.
3. Solve the system of equations:
[tex]\left\{\begin{array}{l}30x+30y=450\\20x+25y=345.\end{array}\right.[/tex]
Divide the first equation by 30 and the second one by 5:
[tex]\left\{\begin{array}{l}x+y=15\\4x+5y=69.\end{array}\right.[/tex]
From the first equation [tex]x=15-y[/tex] and
[tex]4(15-y)+5y=69,\\ \\60-4y+5y=69,\\ \\y=9\ ft^2.[/tex]
Then [tex]x=15-9=6\ ft^2.[/tex]
Paul can shovel [tex]9-6=3\ ft^2[/tex] more than Melinda can.
Answer:
Paul can shovel 3 square feet more than Melinda in one minute.
Step-by-step explanation:
Let Melinda shovels driveways in x square feet in one minute and Paul shovels y square feet in one minute.
From first statement of the question.
Together they shoveled 450 square feet in 30 minutes.
Then equation will be 30x + 30y = 450
We solve it further dividing by 30 on each side of the equation.
x + y = 15 -------(1)
Second statement says Melinda shoveled for 20 minutes and Paul shoveled for 25 minutes to complete 345 sq. feet.
The equation will be 20x + 25y = 345
Further we divide the equation by 5
4x + 5y = 69--------(2)
Now we multiply equation 1 by 4 and subtract it from equation 2.
(4x + 5y) - (4x + 4y) = 69 - 60
y = 9
by putting the value of y in equation number 1.
x + 9 = 15
x = 15 - 9 = 6
Now we have to find the difference between per minute shovel done by Paul and Melinda.
y - x = 9 - 6 = 3
Therefore Paul can shovel 3 square feet more than Melinda.