Question

The molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?

Answer 1

The chemical reaction would be as follows:
2LiOH + CO2 = Li2CO3 + H2O

We are given the amount of the CO2 to be used in the reaction. We use this to calculate the amount of LiOH. We do as follows:

25.5 g CO2 ( 1 mol / 44.01 g ) ( 2 mol LiOH/1 mol CO2)  = 1.16 mol LiOH needed

Answer 2

Answer : The moles of $LiOH$ needed are, 1.158 moles

Explanation : Given,

Mass of $CO_2$ = 25.5 g

Molar mass of $CO_2$ = 44.01 g/mole

First we have to calculate the moles of $CO_2$.

$\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}=\frac{25.5g}{44.01g/mole}=0.579moles$

Now we have to calculate the moles of $LiOH$

The balanced chemical reaction will be,

$2LiOH+CO_2\rightarrow Li_2CO_3+H_2O$

From the balanced chemical reaction we conclude that,

As, 1 mole of $CO_2$ react with 2 moles of $LiOH$

So, 0.579 mole of $CO_2$ react with $2\times 0.579=1.158$ moles of $LiOH$

Therefore, the moles of $LiOH$ needed are, 1.158 moles