Respuesta :
My solution to the problem is as follows:
x=number of phones
per dayselling price per day:p(x)=110−0.1x
cost price per day:c(x)=50x+4000
profit:P(x)=p(x)−c(x)
I hope my answer has come to your help. God bless and have a nice day ahead!
x=number of phones
per dayselling price per day:p(x)=110−0.1x
cost price per day:c(x)=50x+4000
profit:P(x)=p(x)−c(x)
I hope my answer has come to your help. God bless and have a nice day ahead!
Hello there.
A company has started selling a new type of smartphone at the price of $110-0.1x where x is the number of smartphones manufactured per day. the parts for each phone cost $50 and labor and overhead for running the plant cost $4000 per day. How many smartphones should the company manufacture and sell per day to maximize profit?
profit:P(x)=p(x)−c(x)
A company has started selling a new type of smartphone at the price of $110-0.1x where x is the number of smartphones manufactured per day. the parts for each phone cost $50 and labor and overhead for running the plant cost $4000 per day. How many smartphones should the company manufacture and sell per day to maximize profit?
profit:P(x)=p(x)−c(x)