Question

1. Graph the six terms of a finite series where a1 = 5 and r = 1.25.

Answer 1

For the answer to the question above, asking to graph the six terms of a finite series where a1 = 5 and r = 1.25.
I'll provide the answer with the solutions below.
a1 = 5 
a2 = 5*r = 5*(5/4) = 25/4 
a3 = 5*r² = 5*(5/4)² = 125/16 
a4 = 5*r³ = 5*(5/4)³ = 625/256 
a5 = 5*r⁴ = 5*(5/4)⁴ = 3125/1024
I hope this helps

Answer 2

The six terms of a finite series where a1 = 5 and r = 1.25 are;

• a(2) = a1 × (1.25)^(2-1) = 6.25
• a(3) = a1 × (1.25)^(3-1) = 7.8125
• a(4) = a1 × (1.25)^(4-1) = 9.7656
• a(5) = a1 × (1.25)^(5-1) = 12.2070
• a(6) = a1 × (1.25)^(6-1) = 15.2588

Terms of finite series

According to the question;

• The first term of the series is; 5
• The common ratio of the series is; 1.25 = (5/4)

The terms of the series can be obtained from the general formula;

• a(n) = a1 × (1.25)^(n-1)

The terms are as follows;

• a(2) = a1 × (1.25)^(2-1) = 6.25
• a(3) = a1 × (1.25)^(3-1) = 7.8125
• a(4) = a1 × (1.25)^(4-1) = 9.7656
• a(5) = a1 × (1.25)^(5-1) = 12.2070
• a(6) = a1 × (1.25)^(6-1) = 15.2588

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