Answer:
[tex]D=2\sqrt{\frac{A}{3.14}}[/tex]
Step-by-step explanation:
we know that
The area of a circle is
[tex]A=3.14r^{2}[/tex] ----> equation A
The diameter of a circle is
[tex]D=2r[/tex] ----> equation B
Solve for r in the equation A
That means ---> isolate the variable r
Divide by 3.14 both sides
[tex]\frac{A}{3.14}=r^{2}[/tex]
take the square root both sides
[tex]\sqrt{\frac{A}{3.14}}=r[/tex]
Rewrite
[tex]r=\sqrt{\frac{A}{3.14}}[/tex]
Substitute the value of r in the equation B
[tex]D=2\sqrt{\frac{A}{3.14}}[/tex]