Suppose that AD,BC,AC and BD are line segments with line AD parallel to line BC. If AD=3, BC=1, and the distance from AD to BC is 5, then what is the altitude of the smaller triangle?

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The best and most correct answer in this question is

(1) h+k=5 

(2)k=3h 

h+3h=5 

h= 5/4 or 1.25 units

    
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