Question

A car slows down from +40 m/s to a complete stop in 10 s. What is its
acceleration?

Answer 1

Answer:

-4 [m/s²].

Explanation:

1) formula of the required acceleration is

a=(V-V₀)/t, where V - final velocity, V₀ - initial velocity [40m/s], t - elapsed time (10s).

According to the condition the final velocity V=0, then

2) a=(0-40)/10= -4 [m/s²].