Question

Given MN shown below with M (-6,1) and N (3,-5) find the equation of the line that runs through P and is parallel to Mn. please show all work.

Answer 1

Answer:

y = $-\frac{2}{3}x$ + 5

Step-by-step explanation:

Find the slope of MN, which is $\frac{1-(-5)}{-6-3} = \frac{6}{-9} = -\frac{2}{3}$

Then, use the formula: y-y₁ = m(x-x₁)

Use point P as (x₁, y₁)

Plugging in x₁ = 6 and y₁ = 1 and simplifying, we find that:

y - 1 = $-\frac{2}{3}$ (x - 6)

Simplify to find that:

y = $-\frac{2}{3}x$ + 4 + 1

y = $-\frac{2}{3}x$ + 5