The answer is 59.08 sq ft.
Lets a be the side length and h be the height of the square pyramid.
Given side length of 4 ft and slant height of 5 ft.
[tex]a^{2} +2a\sqrt{\frac{a^{2} }{4} +h^{2} } \\=4^{2} + 2 .4.\sqrt{\frac{4^{2} }{4} +5^{2} } \\=59.08[/tex]
How do you find the surface area of a square pyramid?
The surface area of a square pyramid is the sum of the areas of all its 4 triangular side faces with the base area of the square pyramid. If a, h, and l are the base length, the height of the pyramid, and slant height respectively, then the surface area of the square pyramid = [tex]a^{2} +2al[/tex] (or) [tex]a^{2} +2a\sqrt{\frac{a^{2} }{4} +h^{2} }[/tex].
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