Question

Find the area of ABF. Round the area to the nearest whole number if necessary.

Answer 1

Answer:

$6$

Step-by-step explanation:

We see that the triangle is a right triangle. We need to find the lengths of the two legs to find the area, then. Let's start with AB.

$AB=\sqrt{(3-1)^2+(0-(-2))^2}=\sqrt{2^2+2^2}=\sqrt{8}=2\sqrt{2}$

Now, we do the other leg.

$\sqrt{(1-4)^2+(-2-(-5))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$.

That will make the area $b*h/2=2\sqrt{2}*3\sqrt{2}/2=6*2/2=6$